Need only the result of copyright and license.

[SaravanaRaja88]

Hi,

I would like to have a tabular view of the copyright and license details. I dont want to list the file details to be present in my final html output file. Is this supported by scancode.

Thanks,
Saravana Raja

[pombredanne]

@SaravanaRaja88 If you are doing this because of #1309 ... then see #1309 (comment)

Otherwise, you can create a custom template to output the things you want the way you like and only the things you want.
For this use these two options:

    --custom-output FILE    Write scan output to FILE formatted with the custom
                            Jinja template file.
    --custom-template FILE  Use this Jinja template FILE as a custom template.

and to get an example of the Jinja template, see https://github.com/nexB/scancode-toolkit/blob/b51c74a3f61bde107f0c93e6312449e5741f896e/src/formattedcode/templates/html/template.html

The data passed down to the template are defined here: https://github.com/nexB/scancode-toolkit/blob/b51c74a3f61bde107f0c93e6312449e5741f896e/src/formattedcode/output_html.py#L240

But as said before, the best is likely to use the standard JSON output and the AboutCode manager app to browse the results https://github.com/nexB/aboutcode-manager

[pombredanne]

@SaravanaRaja88 ping? any feedback?