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Another Solution for leetcode java 1217 #182
Description
class Solution {
public int minCostToMoveChips(int[] position) {
int even = 0;
int odd = 0;
for(int i : position) {
if(i % 2 == 0) even++;
else odd++;
}
return Math.min(even, odd);
}
}
This solution is much easier to understand. Actually i am learning and building my skills for open source so please assign me this issue to help me grow !
Activity
NeuYash commentedon Jul 12, 2024
class Solution {
public int minCostToMoveChips(int[] position) {
int num=0;
for(int i: position){
num+=i%2;
}
return Math.min(num, position.length-num);
}
Here I am trying to count odd elements, get its complement for even elements, and do Math. min on those.